Respuesta :
$1.21
Further explanation
Given:
- A toy airplane costs $4.84.
- It costs 4 times as much as a toy car.
Question:
What is the cost of the toy car?
The Process:
Let the cost of the toy car as C.
A toy airplane costs $4.84. It costs four times as much as a toy car.
From this statement, it is quite clear that the cost of a toy airplane is four times more expensive than a toy car.
We write the equation as follows:
[tex]\boxed{ \ C \times 4 = \$4.84 \ }[/tex]
Both sides are divided by 4 to get the value of C.
[tex]\boxed{ \ C \times 4 \div 4 = \$4.84 \div 4 \ }[/tex]
[tex]\boxed{ \ C \times 1 = \$1.21 \ }[/tex]
[tex]\boxed{\boxed{ \ C = \$1.21 \ }}[/tex]
From the initial process above, we can immediately divide it like a fraction. See the following.
[tex]\boxed{ \ C \times 4 = \$4.84 \rightarrow C = \frac{\$4.84}{4} = \boxed{ \ \$1.21 \ }\ }[/tex]
Thus, the cost of the toy car is $1.21.
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Keywords: a toy airplane, costs, $4.84, four times as much as a toy car, 4, more expensive, divide, fraction
![Ver imagen BladeRunner212](https://us-static.z-dn.net/files/d73/0d771eecacb5c3bc2752e2f10639c02e.png)
The cost of toy car is [tex]\boxed{\bf \$1.21}[/tex].
Further explanation:
Given:
There is a toy airplane costs [tex]\$\ 4.84[/tex] and it costs [tex]4[/tex] times as much as a toy car.
Calculation:
Division is one of the basic arithemetic operation. This is an operation which is used whenever we divide a quanity into equal number of parts and the result obtained after the division is the weightage of each part.
For example:
There are two numbers [tex]20\text{ and }5[/tex] then divide [tex]20[/tex] by [tex]5[/tex] as follows:
[tex]\boxed{\dfrac{20}{5}=4}[/tex]
Therefore, [tex]4[/tex] is the number obtained after division.
In the question it given that toy airplane costs [tex]\$\ 4.84[/tex] and its cost [tex]4[/tex] times of toy car and we need to find the cost of toy car.
As it cost is [tex]4[/tex] times the toy car then we have to divide the cost of toy airplane [tex]\$\ 4.84[/tex] by [tex]4[/tex] to obtain he cost of toy car suppose [tex]C[/tex].
[tex]\begin{aligned}C&=\dfrac{4.84}{4}\\&=1.21\end{aligned}[/tex]
Therefore the cost of toy car is [tex]\boxed{\$\ 1.21}[/tex].
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Answer details:
Grade: Junior school
Subject: Mathematics
Chapter: Multiplication and division
Keywords: Toy, car, airplane, 4 times, simplification, cost, multiplication, division, addition, subtraction, real numbers, decimal numbers, arithmetic.