Given: m arc IV =114°, m∠VSK=38° Find: m PK
![Given m arc IV 114 mVSK38 Find m PK class=](https://us-static.z-dn.net/files/d1e/819154d6ddb1febb6bed81f6543d4388.png)
Answer:
The measure of arc PK is [tex]170\°[/tex]
Step-by-step explanation:
step 1
Find the measure of angle ISV
we know that
[tex]m<ISV+m<VSK=180\°[/tex] -----> by supplementary angles
we have
[tex]m<VSK=38\°[/tex]
substitute
[tex]m<ISV+38\°=180\°[/tex]
[tex]m<ISV=180\°-38\°=142\°[/tex]
step 2
Find the measure of arc PK
we know that
The measure of the inner angle is the semi-sum of the arcs comprising it and its opposite
Let
x-----> the measure of arc IV
y-----> the measure of arc PK
[tex]m<ISV=\frac{1}{2}(x+y)[/tex]
substitute the values and solve for y
[tex]142\°=\frac{1}{2}(114\°+y)[/tex]
[tex]284\°=(114\°+y)[/tex]
[tex]y=284\°-114\°=170\°[/tex]