A small bay system contains 8.5x108L of 35ppt seawater. At this salinity, there are 1.9g/L Mg2 and 3.2g/L SO42-. How much of this bay’s seawater is MgSO4 (in kg)?

Respuesta :

To calculate the amount of MgSO4 in the bay's seawater in kilograms, you can follow these steps:

1. **Calculate the amount of Mg2 and SO42- in the seawater**:

- Mg2: 1.9g/L * 8.5x10^8 L = total grams of Mg2 in the bay's seawater

- SO42-: 3.2g/L * 8.5x10^8 L = total grams of SO42- in the bay's seawater

2. **Calculate the molar mass of MgSO4**:

- Mg: 24.305 g/mol

- S: 32.065 g/mol

- O (4 atoms): 15.999 g/mol * 4 = 63.996 g/mol

- Total molar mass of MgSO4 = 24.305 + 32.065 + 63.996 = X g/mol

3. **Calculate the amount of MgSO4 in the bay's seawater**:

- Convert the total grams of Mg2 and SO42- to moles

- Determine the molar ratio of Mg2 to MgSO4 and SO42- to MgSO4

- Calculate the total moles of MgSO4 in the seawater

- Convert the total moles to kilograms

By following these steps, you can determine the amount of MgSO4 in the bay's seawater in kilograms based on the provided concentrations of Mg2 and SO42- at a salinity of 35ppt. This calculation allows you to understand the composition of the seawater and the presence of MgSO4 within it.

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