Give the equation of the graph:
[tex]\text{ f(x) = }\lvert x-2\rvert\text{ + 3}[/tex]If it's been shifted by one unit to the left and two units downward, it means that the x-intercept will be subtracted by one unit and its y-intercept will be subtracted by two units.
Let,
g(x) = the new equation after being shifted
We get,
[tex]\text{ f(x) = }\lvert x-2\rvert\text{ + 3 }\rightarrow g(x)\text{ = f(x-1) - 2}[/tex][tex]g(x)\text{ = }\lvert(x-1)-2\rvert\text{ + 3 - 2}[/tex][tex]\text{ g(x) = }\lvert x-3\rvert\text{ + 1}[/tex]Therefore, the new equation of the graph after being shifted will be g(x) = Ix-3I + 1.