Respuesta :

Using synthetic division we get:

Therefore:

[tex]\frac{3x^3+2x^2-6x+9}{x-5}=3x^2+17x+79+\frac{404}{x-5}\text{.}[/tex]

Answer:

[tex]3x^2+17x+79+\frac{404}{x-5}\text{.}[/tex]

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