Question

Suppose an egyptian mummy is discovered in which the amount of​ carbon-14 present is only about oneone​-fifthfifth the amount found in living human beings. the amount of​ carbon-14 present in animal bones after t years is given by yequals=y 0 e superscript negative 0.0001216 ty0e−0.0001216t​, where y 0y0 is the amount of​ carbon-14 present in living human beings. about how long ago did the egyptian​ die?

Answer 1

We are given the following equation:

y = y0 e^-0.0001216 t

where y = 1/5 y0, y0 is the original amount

So solving for time t:

1/5 y0= y0 e^-0.0001216 t

t = 13,235.51 years

 

So the human died about 13235.5 years ago

Answer 2

The Egyptian mummy discovered has been died 13235.5 years ago.

To calculate and solve for the time required for the presence of carbon-14, the carbon dating profile of the bones has been considered. The radiocarbon dating with carbon-14 helps in the determination of the age of objects by carbon profiling.

$\rm y = y_{0} \;e{-0.0001216}t$

y0 has been the amount of carbon present in living beings.

Given,

$\rm y = 1/5 y_{0},$

For time,

$\rm 1/5 y_{0}= y_{0} e{-0.0001216}t$

$\rm t = 13,235.51 \;years$

Thus, the Egyptians mummy discovered has died 13235.5 years ago.

Learn more about carbon dating, refer to the link:

https://brainly.com/question/18945700