Question

What is the sum of the polynomials?(8x2-9y2-4x)+(x2-3y2–7x)7x2 - 6y2 + 3x9x2 - 6y2+3x9x2 - 12y2 + 3x9x2 - 12/2 - 11x

Answer 1

Let's simplify the following expression:

$\text{ (8x}^2-9y^2-4x)+(x^2-3y^2-7x)$

We get,

$\text{ (8x}^2-9y^2-4x)+(x^2-3y^2-7x)$$\text{ 8x}^2-9y^2-4x+x^2-3y^2-7x$

Let's put like terms beside each other and proceed with the operation:

$\text{ 8x}^2-9y^2-4x+x^2-3y^2-7x$$\text{ 8x}^2+x^2-9y^2-3y^2-7x-4x$$\text{ (8x}^2+x^2)+(-9y^2-3y^2)+(-7x-4x)$$\text{ (9x}^2^{})+(-12y^2)+(-11x)$$\text{ 9x}^2-12y^2-11x$

Therefore, the sum of the given polynomials (8x^2-9y^2-4x)+(x^2-3y^2–7x) is 9x^2 - 12y^2 - 11x.

The answer is letter D.