Respuesta :
Let the smallest integer be x
x + (x+2) + (x+4) + (x+6) = 288
4x +12 =288
4x= 276
x = 69
The integers are 69, 71, 73 and 75
x + (x+2) + (x+4) + (x+6) = 288
4x +12 =288
4x= 276
x = 69
The integers are 69, 71, 73 and 75
The set of consecutive odd integers which adds up to 288 are ; 69, 71, 73 and 75 respectively.
Let the consecutive odd integers be :
- a, a+2, a+4, a+6
The sum can be expressed thus :
a + a + 2 + a + 4 + a + 6 = 288
4a + 12 = 288
4a = 288 - 12
4a = 276
a = 276 / 4
a = 69
Therefore, the consecutive odd integers are : 69, 71, 73, 75
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