Question

A ball is thrown in the air. The path of the ball is represented by the equation h(f)=-f+&tGraph the equation over the interval Ost<8 on the following graph.2.What is the maximum height of the ball? 16 metersb.How long is the ball above 7 meters?8 secondsc. Rewrite the equation in vertex form.

Answer 1

Given the following question:

$\begin{gathered} x=\frac{-b}{2a} \\ \frac{-8}{2(-1)}=\frac{8}{2}=4 \\ y=-(4)^2+8(4) \\ -16+32=16 \\ Vertex=(4,16) \\ \text{ Vertex form} \\ y=-(x-4)^2+16 \\ \end{gathered}$

Speaking how the maximum height is 16 meters and the vertex is (4, 16)