Question

are 7 yellow, 6 blue, 2 red and 3 green ribbons in a drawer. Once a non selected not toplowing probability:n and then a red ribbon)7

Answer 1

Concept

Probability of any event

= number of required outcomes / total number of possible outcomes

Yellow = 7

Blue = 6

Red = 2

Green = 3

Total = 18

Probability of selecting the first ball (green) without replacement

= 3/18 = 1/6

Since the first ribbon is not replaced, the total reduces to 17.

Probability of selecting the second ball (red).

= 2/17

Therefore the probability of selecting green and then red ribbon

' and ' means multiplication

$\begin{gathered} \text{ = }\frac{1}{6}\text{ }\times\text{ }\frac{2}{17} \\ =\text{ }\frac{1}{3}\text{ }\times\text{ }\frac{1}{17} \\ =\text{ }\frac{1}{51} \end{gathered}$

Final answer

Option C = 1/51