Respuesta :
The first step is to make a balanced chemical equation.
2AgNO3 + CaCl2 ---> 2AgCl + Ca(NO3)2
Molecular Weights:
CaCl2 = 110.98 g/mol
AgNO3 =170.01
AgCl: 143.45 g/mol
Volume:
CaCl2: 30.0mL=0.03L
AgNO3: 15.0mL=0.015 L
Solving for the limiting reactant one needs to get the mols CaCl2 and mols AgNO3:
CaCl2: 0.150M(mol/L) * 0.03L = 0.0045 moles
AgNO3: 0.100M*0.015L = 0.0015 moles
Since the stoichiometric ratio of AgNO3 to CaCl2 is 2:1
0.0015 mols AgNO3 *(1 mol CaCl2/ 2 mols AgNO3) = 0.00075 mols CaCl2
Since the answer is lesser than CaCl2 then the limiting reactant is AgNO3.
To get the mass of AgCl one will do a stoichiometric calculation with respect to the limiting reactant, AgNO3.
0.0015 moles AgNO3
A solution of silver nitrate is combined with a solution of sodium chloride. The resulting solution contains Na+, Ag+, Cl-, and NO3-, but AgCl is not soluble in water. Since Ag+ is now in solution with Cl- the two will combine to form AgCl, and the AgCl will precipitate from solution.
Almost all alkali metal compounds and nitrates are soluble, but most silver compounds are insoluble (except for acetates, perchlorates, chlorates, and nitrates). Therefore, when the soluble salts silver nitrate and sodium chloride are mixed, insoluble silver chloride forms and precipitates out.
To learn more about AgCl precipitate refer here:
https://brainly.com/question/17102479
#SPJ4
