Respuesta :
A chemist reacted 0.2 moles of sodium benzoate with 0. 25 moles of hydrochloric acid. if she generated 22 g benzoic acid, the percent yield is 90%.
The Percentage ratio of the theoretical yield to the actual yield is known as the percent yield. It is calculated as the theoretical yield multiplied by 100% divided by the experimental yield. The percent yield is 100% if the theoretical and actual yields are equal.
Reactant + HCl ------ Product
0.2 mol 0.25 22g
mol
Number of moles of reactant = 0.2mol
The molar mass of the product = 122.12g
Number of moles of product = given mass/ molar mass
Number of moles of product = 22g / 122.12 g
Number of moles of product = 0.180mol
Percent yield = (number of moles of product/ number of moles of reactant) × 100
Percent yield = (0.180/0.2) × 100
Percent yield = 90%
Thus we concluded that the percent yield of the given solution is 90%.
To know more about percent yield refer to: https://brainly.com/question/17042787
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