Question

What is the value of "c" in the following quadratic? (Make sure the equation is in
standard form: ax^2 + bx +c= 0)
X^2 +28 = -11x

Answer 1

               $\rule{50}{1}\large\blue\textsf{\textbf{\underline{Given question:-}}}\rule{50}{1}$

           What is the value of c in the quadratic $\large\text{ x^2+28=-11x }$?

          $\rule{50}{1}\large\textsf{\textbf{\underline{Answer and how to solve:-}}}\rule{50}{1}$

           Before starting to solve, you should notice something - the

quadratic is not in its standard form!

We can easily fix it by adding $\large\textit{11x}$ on both sides:-

$\large\text{ x^2+28-11x=0 }$

We can switch the order of 28 and -11x:-

$\large\text{ x^2-11x+28=0 }$

  Now, the quadratic is in its standard form, so we can get down to

finding the value of "c".

Remember, the standard form of a quadratic looks like so:-

•  $\large\text{ ax^2+bx+c=0 }$

Now we can just write our quadratic here:-

• $\large\text{ x^2-11x+28=0 }$

Now, can you see what the value of "c" is?

An easy way to remember "c" in quadratics is:-

The "c" in quadratics is the constant.

   

Henceforth, we conclude that the value of "c" in the given quadratic is:-

 $\Large\textbf{28}\Large\checkmark$

        Good luck with your studies.

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