Respuesta :
Hello,
x^2+y^2+8x-6y+21=0
Rewritten in the form of a standard circle equation:
(x-(-4))^2+(y-3)^2=2^2
Therefore, the circle properties are:
(a,b)=(-4,3),r=2
The radius of the circle whose equation is x^2 + y^2 + 8x - 6y + 21 =0 is 2.
Faith xoxo
x^2+y^2+8x-6y+21=0
Rewritten in the form of a standard circle equation:
(x-(-4))^2+(y-3)^2=2^2
Therefore, the circle properties are:
(a,b)=(-4,3),r=2
The radius of the circle whose equation is x^2 + y^2 + 8x - 6y + 21 =0 is 2.
Faith xoxo
the standard form of a circle is (x-h)²+(y-k)²=r², (h,k) being the coordiantes of the center, r being the radius.
rearrange the equation:
x²+8x+y²-6y=-21
make squares by adding (half of b)². b in this case being 8 for x, and -6 for y:
so add 4² and (-3)²:
x²+8x+4²+y²-6y+(-3)²=-21+4²+(-3)²
(x+4)²+(y-3)²=2²
so the radius is 2
rearrange the equation:
x²+8x+y²-6y=-21
make squares by adding (half of b)². b in this case being 8 for x, and -6 for y:
so add 4² and (-3)²:
x²+8x+4²+y²-6y+(-3)²=-21+4²+(-3)²
(x+4)²+(y-3)²=2²
so the radius is 2
