Question

Using the initial concentration and volume values from Trial 1 of Table 1, fill in the following chart of new concentration values (in Molarity) for the following reactants:

Answer 1

Based on the volume and concentration of the solutions given;

• Molarity of KBrO3 = 0.02 M
• Molarity of Na2S2O3 = 0.05 M
• Molarity of KBrO3 = 0.02 M
• Molarity of Na2S2O3 = 0.05 M

What is molarity?

Molarity of a solution is the concentration of the solution given as number of moles of solute in a given volume of solution in litres.

• Molarity = number of moles/volume in Litres

The molarity of each of the solutes in the solution are as follows:

Flask A:

Total volume = 15 mL = 0.015 L

moles of KI = 0.01 M × 0.005 L = 0.00005 moles

moles of Na2S2O3 = 0.001 M × 0.005 = 0.000005 moles

Molarity of KI = 0.00005 moles/0.015 L

Molarity of KI = 0.0033 M

Molarity of Na2S2O3 = 0.000005 moles/0.015 L

Molarity of Na2S2O3 = 0.00033 M

Flask B:

Total volume = 10 mL = 0.001 L

moles of KBrO3 = 0.04 M × 0.005 L = 0.0002 moles

moles of HCl = 0.1 M × 0.005 = 0.0005 moles

Molarity of KBrO3 = 0.0002 moles/0.01 L

Molarity of KBrO3 = 0.02 M

Molarity of Na2S2O3 = 0.0005 moles/0.01 L Molarity of Na2S2O3 = 0.05 M

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