Answer:
Your question is lacking some information attached is the missing part and the solution
A) AB = AD = BD = 0, BC = LC
AC = [tex]\frac{5L}{3}T, CD = \frac{4L}{3} C[/tex]
B) AB = AD = BC = BD = 0
AC = [tex]\frac{5L}{3} T, CD = \frac{4L}{3} C[/tex]
Explanation:
A) Forces in all members due to the load L in position A
assuming that BD goes slack from an inspection of Joint B
AB = 0 and BC = LC from Joint D, AD = 0 and CD = 4L/3 C
B) steps to arrive to the answer is attached below
AB = AD = BC = BD = 0
AC = [tex]\frac{5L}{3} T, CD = \frac{4L}{3}C[/tex]