The mass of oxygen produced when 68 g of hydrogen peroxide decomposes is 32g.
Relation between the mass and moles of any substance will be represented as:
n = W/M, where
Chemical reaction:
2H₂O₂ → 2H₂O + O₂
Moles of 68g of H₂O₂ = 68g / 34g/mol = 2mol
From the stoichiometry of the reaction:
2 moles of H₂O₂ = produces 1/2×2 = 1 mole of O₂
Mass of 1 mole of O₂ = (1mol)(32g/mol) = 32g
Hence required mass of oxygen is 32g.
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