Answer:
The answer is neither.
Step-by-step explanation:
We need to solve for y in the equation, 10x-2y= 6.
In other words, we are going to find the slope intercept of that equation.
[tex]10x - 2y = 6 \\ \frac{ + 10x = + 10x}{ - 2y = 10x + 6} \\ \\ \frac{ - 2y }{ - 2} = \frac{10x + 6}{ - 2} \\ y = - 5x - 3[/tex]
So we have now have both the equations:
[tex]y = 5x + 2 \\ and \\ y = - 5x - 3[/tex]
It's not parallel because the slopes aren't the same. It's not perpendicular because when the slope of the equation becomes a negative reciprocal, it still doesn't end up with the same slope as the other equation.
It's neither parallel or perpendicular.
