Question

Using the completing-the-square method, rewrite f(x) = x^2-6x+2 in vertex form.
A f(x)= (x-3)^2
B f(x)= (x-3)^2 +2
C f(x)= (x-3)^2 -7
D f(x)= (x-3)^2 +9

Answer 1

Answer:

Option C.  f(x)= (x-3)^2 -7

Step-by-step explanation:

we have

$f(x)=x^2-6x+2$

step 1

Complete the square

Remember to balance the equation by adding the same constants to each side.

$f(x)=(x^2-6x+3^2)+2-3^2$

$f(x)=(x^2-6x+9)-7$

step 2

Rewrite as perfect squares

$f(x)=(x-3)^2-7$

The vertex is the point (3,-7)