Question

Find the first 3 iterations of the function f(x)=1/3x+1 if you have an initial value of 2

Answer 1

Answer:

5/3, 14/9, 41/27

Step-by-step explanation:

f(x) = (⅓)x + 1

x=0 = 2

x1 = (⅓)(2) + 1

= ⅔ + 1

x1 = 5/3

x2 = (⅓)(5/3) + 1

= 5/9 + 1

x2 = 14/9

x3 = (⅓)(14/9) + 1

= 14/27 + 1

x3 = 41/27