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The equation of the graphed line in point-slope form is , and its equation in slope-intercept form is .

Select the correct answer from each dropdown menuThe equation of the graphed line in pointslope form is and its equation in slopeintercept form is class=

Respuesta :

y = -3/5(x-3)

y= (-3/5) x + 9/5

Step-by-step explanation:

Step 1 :

The equation of line in point and slope form is (y- y intercept) = m(x-x intercept)

Where m represents the slope and x1 and y1 are points on the line.

Given (-2,3) and (3,0) are points on the line

m = (y2-y1)/(x2-x1) = (0-3)/(3-(-2)) = -3/5

So the equation of the line in point slope form is

(y-0)= -3/5(x-3) = y = -3/5(x-3) [taking the point as (3,0)]

Step 2 :

The equation of a line in slope and intercept form is  y = m x +c

m denotes the slope and the constant c denotes the y intercept (the value of intercept in the y axis when x = 0)

when x = 0, y = 9/5 [using the equation in step 1]

Hence the equation in slope and intercept form is

y= (-3/5) x + 9/5

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