Question

In studying the gene pool of a population, you find that 15% of the population is homozygous recessive (tt) for a trait. How would you use this information to solve for the frequency of the dominant T allele?

Square root of 0.15
1–Square root of 0.15
15 ÷ 100
0.152

Answer 1

Answer:

The correct answer would be 1–Square root of 0.15.

It can be solved with the help of Hardy-Weinberg equations; p + q = 1.

Where p indicates the frequency of a dominant allele in a population and q indicates the frequency of the recessive allele in a population.

The percentage of the individual with homozygous recessive genotype is 15%.

Thus, the value of q² = 0.15

So, q = $\sqrt{0.15}$ ≈ 0.387

The value of p would be equal to 1 - 0.387 ⇒ 0.613

Answer 2

Answer:

The answer is 1 - Square root of 0.15

Explanation:

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