Question

Find dy/dx if x^2y^2 - 3x = 5

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Answer 1

Answer:

y' = $\frac{3-2xy^2}{x^22y}$

Explanation:

Use implicit differentiation:

2x * y^2 + x^2 * 2y * y' – 3 = 0

x^2 * 2y * y' = 3 - 2x * y^2

y' = $\frac{3-2xy^2}{x^22y}$