Using the normal distribution, the indicated IQ score is of 108.025.
The z-score of a measure X of a normally distributed variable with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex] is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The mean and the standard deviation are given, respectively, by:
[tex]\mu = 100, \sigma = 15[/tex].
The shared region is the region to the right, hence it has a p-value of 1 - 0.2969 = 0.7031, which means that Z = 0.535. Then the IQ score is found as follows:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
0.535 = (X - 100)/15
X - 100 = 0.535 x 15
X = 108.025.
More can be learned about the normal distribution at https://brainly.com/question/15181104
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