Answer:
Acceleration of the car, [tex]a=6.16\ m/s^2[/tex]
Explanation:
It is given that,
Mass of the car, m = 1230 kg
The car is inclined at an angle of 39 degrees.
The acceleration of gravity acting on the car is [tex]9.8\ m/s^2[/tex]. The component of car parallel to inclined planes is :
[tex]W_x=mg\ sin\theta[/tex]
Net force acting on it is :
[tex]ma=mg\ sin\theta[/tex]
[tex]a=g\ sin\theta[/tex]
[tex]a=9.8\times \ sin(39)[/tex]
[tex]a=6.16\ m/s^2[/tex]
So, the acceleration of the car is [tex]6.16\ m/s^2[/tex]. Hence, this is the required solution.