Question

How many moles of carbon dioxide are produced from 148 g of acetylene

Answer 1

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Answer 2

Answer:- 11.4 g of $CO_2$ are produced by the combustion of 148 g of acetylene.

Solution:- Acetylene is a hydrocarbon that gives carbon dioxide on combustion in presence of oxygen. The balanced equation for the combustion of acetylene is:

$2C_2H_2+5O_2\rightarrow 4CO_2+2H_2O$

From balanced equation, there is 2:4 mol ratio between acetylene and carbon dioxide.

First of all we convert grams of acetylene to moles on dividing it's grams by molar mass of it. Then in next step, we multiply by mol ratio to get the moles of carbon dioxide.

Molar mass of acetylene is 26 . The set up would be as:

$148g C_2H_2(\frac{1molC_2H_2}{26g C_2H_2})(\frac{4 mol CO_2}{2mol C_2H_2})$

= 11.4 mol $CO_2$

So, 11.4 moles of $CO_2$ are produced by the combustion of 148 g of acetylene.