Answer:
3 feet wide and 9 feet long.
Step-by-step explanation:
The classroom wall has an area of [tex]90ft^2[/tex].
The fire code requirements allow a bulletin board with an area of at most 30% of [tex]90ft^2[/tex]. This means that the maximum area of the bulletin board is [tex]27ft^2[/tex]
Let L and W be the length and wide of the bulletin board.
If the length of the board is three times as long as the width, then L=3W, and the area of the board is [tex]LW=3WW=3W^2[/tex]
For the largest board we have, [tex]3W^2=27 \Rightarrow W^2=\frac{27}{3}=9 \Rightarrow W=\sqrt{9}=3ft[/tex]
So, the largest bulletin board that meets the fire code is 3 ft. wide and 9 ft. long.