The heights of 200 adults were recorded and divided into two categories. Which two way frequency table correctly shows the marginal frequencies?

The two way frequency table showing the marginal frequency for the given data is Option B:
[tex]\begin{array}{cccc}&6' \: \rm or \: over&\rm Under \: 6' & \rm Total \\\rm Male&12&86 & 98\\\rm Female&3&99 & 102\\ \rm Total & 15 & 185 & 200 \end{array}[/tex]
Marginal (on the margin) frequencies are sum of all joint frequencies for a given row or for a given column. They care for a specific category and sum all of their frequencies for the second dimension (that means, they do not differentiate between values of second dimension and just take the total frequency of the single considered category.
For the given condition, it is known that there are 200 people. In the given table, let the count of females under 6 feet be [tex]x[/tex]
Then we have:
[tex]200 = 12 + 3 + 86 + x\\x = 99[/tex]
Thus, the complete table will be
[tex]\begin{array}{ccc}&6' \: \rm or \: over&\rm Under \: 6' \\\rm Male&12&86\\\rm Female&3&99\end{array}[/tex]
Now, calculating marginal frequencies:
Two dimensions are there. One dimension differentiates between genders and one dimension differentiates between height under 6', or 6' or over
For first dimension(gender):
Joining all frequency over height dimension, the total of frequencies is
12 + 86 = 98
Joining all frequency over height dimension, the total of frequencies is
3 + 99 = 102
For second dimension(height):
Joining all frequency over Gender dimension, the total of frequencies is
12 + 3 = 15
Joining all frequency over Gender dimension, the total of frequencies is
86 + 99 = 185
Thus, the marginal frequencies will be given as said above. They usually lie on the margin of the table, named as Total.
The two way table will be
[tex]\begin{array}{cccc}&6' \: \rm or \: over&\rm Under \: 6' & \rm Total \\\rm Male&12&86 & 98\\\rm Female&3&99 & 102\\ \rm Total & 15 & 185 & 200 \end{array}[/tex]
Thus,
The two way frequency table which correctly shows the marginal frequency for the given data is given by
Option B:
[tex]\begin{array}{cccc}&6' \: \rm or \: over&\rm Under \: 6' & \rm Total \\\rm Male&12&86 & 98\\\rm Female&3&99 & 102\\ \rm Total & 15 & 185 & 200 \end{array}[/tex]
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