Question

A bag contains 7 red marbles, 6 green marbles, 5 yellow marbles, and 2 orange marbles. marbles are drawn twice with replacement. what is p(yellow, then green)?

Answer 1

Total=7+6+5+2=20
P（yellow）=5/20=¼
P（Green）=6/20=
$\frac{3}{10}$
$p(yellow \: then \: green) = \frac{1}{4 } \times \frac{3}{10} = \frac{3}{40}$