Respuesta :

The given expression is:

[tex] x^{2} +6x=-7 \\ \\ x^{2} +2(x)(3)=-7[/tex]

Adding the square of 3 to both sides, to make the left hand side of the equation a complete square, we get:

[tex] x^{2} +2(x)(3)+ 3^{2}=-7+ 3^{2} \\ \\ (x+3)^{2}=2 \\ \\ x+3=+- \sqrt{2} [/tex]

So the values of x are:

a) [tex]x= \sqrt{2} - 3 = -1.59[/tex]

b) [tex]x= -\sqrt{2} - 3 = -4.41[/tex]
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