Question

What, if any, precipitate forms if aqueous solutions of lead(ii) nitrate (pb(no3)2) and sodium acetate are mixed?

Answer 1

Lead(II) nitrate reacts with sodium acetate to give Lead acetate and sodium nitrate and all of these salts are soluble in water so no precipitate will be formed.
Pb(NO₃)₂(aq) + CH₃COONa(aq) → (CH₃COO)₂Pb(aq) + 2 NaNO₃(aq) 

Answer 2

Answer:

No precipitate forms in this reaction.

Explanation:

It is an example of double displacement reaction.

In double displacement reaction, cations and anions of two salts interchange between themselves.

Here reaction between $Pb(NO_{3})_{2}$ and $Na(CH_{3}COO)$ forms $Pb(CH_{3}COO)_{2}$ and $NaNO_{3}$.

Both $Pb(CH_{3}COO)_{2}$ and $NaNO_{3}$ are soluble in water. Hence no real precipitate forms in this reaction.

Balanced chemical equation:

$Pb(NO_{3})_{2}(aq.)+2Na(CH_{3}COO)(aq.)\rightarrow Pb(CH_{3}COO)_{2}(aq.)+2NaNO_{3}(aq.)$