Question

A clock has radius of 0.5m. The outermost point on its minute hand travels along the edge. What is its tangential speed?

Answer 1

The angular speed of the minute hand is the ratio between the angle covered and the time taken. The angle covered by the minute hand is $2 \pi$, while the time needed is $t=60 min= 3600 s$, so the angular speed is
$\omega = \frac{2 \pi}{3600 s}=0.0017 rad/s$

And the tangential speed is given by
$v=\omega r=(0.0017 rad/s)(0.5 m)=8.72 \cdot 10^{-4} m/s$