Question

For 4 weeks in June, Cameron biked 3 1/4 miles each week and swam 2 1/2 miles each week. For 3 weeks in July, he biked 4 3/4 miles each week and swam 3 1/2 miles each week. How much greater was the total distance Cameron biked and swam in July compare biked and swam in July compared to the total distance he biked and swam in June ? Please help and tell me the steps

Answer 1

To answer this question you will find the total distance biked and swam from each of the months. Once you find individual distances, you add the distances from June together, add the distances from July together, and subtract the distance in June from the distance in July.

Please see the attached t-chart for the work:

In July Cameron biked/swam 24 3/4 miles, and in June he biked/swam 23 miles.

24 3/4 - 23= 1 3/4

He biked/swam 1 3/4 more miles in July.

Answer 2

The total distance Cameron biked and swam in July was 2 2/4 miles = 2.5 miles greater than the total distance he biked and swam in June.

How to convert mixed fraction to simple fraction?

There is a fraction, containing numerator(upper value) and denominator(lower value).

When the numerator is less than the denominator, the fraction is called proper fraction, otherwise it is called improper fraction.

A proper fraction is also called fraction which is less than 1.

And an improper fraction is ≥ 1

A mixed fraction contains a sum of whole number and a proper fraction.

Thus, we have: $a\dfrac{b}{c} = a + \dfrac{b}{c} = \dfrac{a \times c + b}{c}$

How to add two fractions?

Let we have to add two fractions as:

$\dfrac{a_1}{b_1} + \dfrac{a_2}{b_2}$

Then we will find Lowest Common Multiple (LCM) of $b_1$ and  $b_2$. That will help to make the denominators same.

Once the denominators become same, the numerators can add up directly, giving us the final result of addition.

For this case, we're specified that:

For June:

• Cameron travelled for 4 weeks
• He biked $3 \dfrac{1}{4}$  miles each week
• He swam $2\dfrac{1}{2}$ miles each week
  

Total distance he covered in June is:

$D_{june} = 3\dfrac{1}{4} + 2\dfrac{1}{2} = 3 + 2 + \dfrac{1}{4} + \dfrac{1}{2} = 5 + \dfrac{1+2}{4}\\D_{june} = \dfrac{5 \times 4 + 3}{4}= \dfrac{23}{4} = 5.75 \: \rm miles$

For july:

• Cameron travelled for 3 weeks
• He biked $4 \dfrac{3}{4}$  miles each week
• He swam $3\dfrac{1}{2}$ miles each week

Total distance he covered in July is:

$D_{july} = 4\dfrac{3}{4} + 3\dfrac{1}{2} = 4+3 + \dfrac{3}{4} + \dfrac{1}{2} = 7 + \dfrac{3+2}{4}\\\\D_{july} = \dfrac{7 \times 4 + 5}{4}= \dfrac{33}{4} = 8.25 \: \rm miles$

The amount he traveled more in july compared to june is the difference between distance traveled in respective months as:

$\dfrac{33}{4} - \dfrac{23}{4} = \dfrac{10}{4} = 2.5$

10/4 in mixed fraction is:

$\dfrac{10}{4} = \dfrac{2 \times 4 + 2}{4} = 2\dfrac{2}{4}$

Thus, the total distance Cameron biked and swam in July was 2 2/4 miles = 2.5 miles greater than the total distance he biked and swam in June.

Learn more about fraction addition here:

https://brainly.com/question/17544795