28-02-2018
Mathematics

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Integral of y/((y^2)-1)

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LammettHash LammettHash

28-02-2018

Hint: [tex]\dfrac y{y^2-1}=\dfrac y{(y+1)(y-1)}=\dfrac12\left(\dfrac1{y+1}+\dfrac1{y-1}\right)[/tex]

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