Question

A nut mixture of walnuts and cashew nuts at a small fair is $1.00 per pound of walnuts and $3.10 per pound of cashew nuts. Over the entire day, 134 pounds of the nut mixture were sold for $241.10. If p is the number walnuts and n is the number of cashew nuts, then the system of equations that models this scenario is: p+n=134p+3.10n=241.10 Determine the correct description and amount of pounds for walnuts and cashew nuts that were sold.

Answer 1

a) The description given in the problem statement appears to be correct.

b) The solution to the system of equations can be found many ways. Choose your favorite (including posting on Brainly, if you like). It is
.. p = 83
.. n = 51

83 pounds of walnuts and 51 pounds of cashews were sold.

Answer 2

Answer: 83 pounds of walnuts and 51 pounds of cashew nuts.

Step-by-step explanation:

Let p be the amount of pounds for walnuts and n be the amount of pounds for  cashew nuts that were sold.

Given : A nut mixture of walnuts and cashew nuts at a small fair is $1.00 per pound of walnuts and $3.10 per pound of cashew nuts.

Over the entire day, 134 pounds of the nut mixture were sold for $241.10.

Then, system of equation represents the given situation will be :-

$p+n=134----------(1)\\\\p+3.10n=241.10----------(2)$

Eliminate (1) from (2), we get

$2.10n=107.1$

Divide 2.10 from both sides , we get

$n=51$

Put value of n in (1), we get

$p+51=134\\\\\Rightarrow\ p=134-51=83$

Hence, the correct description will be : 83 pounds of walnuts and 51 pounds of cashew nuts.