Question

cells may become dehydrated when water leaves the cell and enters the surrounding environment, leaving the cell limp and shriveled. When this happens, what type of solution is the cell in, and how would taking in water help the cell?

1.) hypertonic; the concentration outside the cell would become less concentrated, and the water would reenter the cell
2.)hypotonic; the concentration outside the cell would become less concentrated, and the water would reenter the cell
3,) hypertonic; the concentration inside the cell would become less concentrated, and the water would reenter the cell
4.) hypotonic; the concentration inside the cell would become less concentrated, and the water would reenter the cell

Answer 1

Water leaves the cell and enters the surrounding environment when the cell is in  an hypertonic solution because water molecules will move by Osmosis from the area of less solute concentration to the are where it is more concentrated. Taking in water will help the cell because the concentration outside the cell would become less concentrated, and the water would then reenter the cell. 

OPTION 1 IS CORRECT

Answer 2

Answer:

1.) hypertonic; the concentration outside the cell would become less concentrated, and the water would reenter the cell

Explanation:

hypertonic solution refers to solution that posses a greater concentration of solutes on the outside of a cell when than the inside of a cell.

In a hypertonic solution, water will leave the cell, and the cell will shrink.

The effects of hypertonic solution in both plant and animal and cell have higher concentration of solutes and less of water than a cell itself, this is because of the higher concentration of water within the cell, so will be net movement of water from inside of the cell to outside of the cell. Therefore, the loss of Water from both vacuole and cytoplasm result to shrinking of cell

Therefore, in hypertonic the concentration outside the cell would become less concentrated, and the water would reenter the cell