Question

What is the value of x?

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x=

A right triangle. The legs are labeled x and six, and the hypotenuse is labeled ten.

Answer 1

We can use the Pythagorean theorum

a^2+b^2=c^2

c^2 is the length of the longest side squared

so 

6^2 + b^2 = 10^2

36+ b^2 = 100
-36               -36

b^2 = 64

b = 8

b is the same thing as your "x", so x = 8

Answer 2

Answer:

$8=x$

Step-by-step explanation:

From the given figure, it is given that ABC is a right angled triangle whch is right angled at B and AC=10, AB=x and BC=6.

Now, since, ABC is a right angled triangle, therefore we can apply the Pythagoras theorem on this triangle, therefore we have

$(AC)^2=(AB)^+(BC)^2$

Substituting the given values, we get

$(10)^2=(x)^2+(6)^2$

$100=x^2+36$

$100-36=x^2$

$64=x^2$

$8=x$

Therefore, the value of x is $8$.