Question

The length of a rectangle is 1 yd more than twice the width, and the area of the rectangle is 28 yd2 . find the dimensions of the rectangle.

Answer 1

Let the width be represented by x. Then the length will be 1+2x, and the area will be
.. A = W*L
.. 28 = x*(1 +2x)
.. 2x^2 +x -28 = 0
.. (2x -7)*(x +4) = 0
.. x = {3.5, -4} . . . . . . . . . . . . width = 3.5. Only the positive solution is of interest
.. 1 +2x = 1 +2*3.5 = 8 . . . . .length

The dimensions of the rectangle are 3.5 yards wide by 8 yards long.