[tex]\bf y=a(b)^t\qquad or\qquad A=I(1-r)^t\qquad \textit{let's check}\\\\
-------------------------------\\\\
\qquad \textit{Amount for Exponential Decay}\\\\
A=I(1 - r)^t\qquad
\begin{cases}
A=\textit{accumulated amount}\\
I=\textit{initial amount}\to &29000\\
r=rate\to 12\%\to \frac{12}{100}\to &0.12\\
t=\textit{elapsed time}\\
\end{cases}
\\\\\\
A=29000(1-0.12)^t\implies
\begin{array}{llll}
A=&29000(0.88)^t\\
&\uparrow \qquad\quad \uparrow \\
&a\qquad\quad b
\end{array}[/tex]
