Question

Match wash hypotenuse length with the leg lengths that will create a right triangle

Answer 1

hope this can help you

Answer 2

Answer:

Step-by-step explanation:

Using the Pythagoras theorem, we have

$(Hyp)^2=(Leg)^2+(Leg)^2$

(A) The given value of hypotenuse is:

$\sqrt{6} units$

Now, using the Pythagoras theorem,

$\sqrt{6}=\sqrt{(\sqrt{5})^2 +(1)^2}$

Thus, one leg is $\sqrt{5} units$ and the other is $1 units$.

(B)The given value of hypotenuse is:

$\sqrt{5} units$

Now, using the Pythagoras theorem,

$\sqrt{5}=\sqrt{(\sqrt{2})^2 +(\sqrt{3})^2}$

Thus, one leg is $\sqrt{2} units$ and the other is $\sqrt{3} units$.

(C) The given value of hypotenuse is:

$\sqrt{8} units$

Now, using the Pythagoras theorem,

$\sqrt{8}=\sqrt{(\sqrt{5})^2 +(\sqrt{3})^2}$

Thus, one leg is $\sqrt{5} units$ and the other is $\sqrt{3} units$.

(D) The given value of hypotenuse is:

$\sqrt{3} units$

Now, using the Pythagoras theorem,

$\sqrt{3}=\sqrt{(\sqrt{2})^2 +(1)^2}$

Thus, one leg is $\sqrt{2} units$ and the other is $1 units$.