The quadratic formula is shown below:
x = (-b±√(b^2-4ac))/2a
You have the equation 3x^2+5x+2 = 0; so "a", "b" and "c" are:
a = 3
b = 5
c = 2
When you substitute a=3, b=5 and c=2 in the Quadratic Formula, you get two roots:
x = (-5±√1)/6
x1 = (-5+1)/6 = -2/3
x2 = (-5-1)/6 = -1
The correct answer is "B":
x = -2/3, -1
