Question

A 50 L cylinder is filled with argon gas to a pressure of 10130.0 kPa at 300°C. How many moles of argon gas does the cylinder contain? (Given: R = 8.314 L∙kPa/K∙mol) 2519.142 mol 506500 mol 203.07 mol 106.32 mol 0.0094 mol

Answer 1

Use the General Gas Law 

PV = nRT => n = PV/ RT

P= 10130.0 kPa
V= 50 L
R= R = 8.314 L∙kPa/K∙mol
T= 300°C + 273 = 573 K

n = 10130.0 kPa 50 L / 8.314 L∙kPa/K∙mol 573 K
n = 106.32 mol

Answer 2

Answer: The moles of argon gas contained in the cylinder is 106.32 mol.

Explanation:

To calculate the number of moles of gas, we use the equation given by Ideal gas, which is:

$PV=nRT$

where,

P = pressure of the gas = 10130 kPa

V = Volume of the gas = 50 L

n = Number of moles of gas = ? moles

R = Gas constant = $8.314\text{ L kPa }K^{-1}mol^{-1}$

T = Temperature of the gas = 300° C = 573 K     (Conversion factor: $T(K)=T(^oC)+273$

Putting values in above equation, we get:

$10130\times 50=n\times 8.314\times 573\\\\n=106.32mol$

Hence, the moles of argon gas contained in the cylinder is 106.32 mol.