Question

Find the equation of the circle if the endpoints of the circle's diameter are (2,-7) and (-6,1).
A.
(x + 6)^2 + (y - 1)^2 = 32
B.
(x + 2)^2 + (y + 4)^2 = 25
C.
(x + 2)^2 + (y + 3)^2 = 32
D.
(x + 2)^2 + (y + 3)^2 = 16

Answer 1

C is correct, because the radius is 4(2)^1/2 so if you square it you will get 32.