Respuesta :
Will do it backward -
the length of the longer leg of triangle ABC = BC
consider one of the small triangles: sin30 = 10/BC
so BC = 10/sin30 = 10/0.5 = 20
the length of the shorter leg of triangle ABC = AC
consider the other small triangles: sin60 = 10/AC
so AC = 10/sin60 = 10/0.866 = 11.55
the length of the hypotenuse of triangle ABC = AB
= sqrt (BC^2 + AC^2) = sqrt (20^2 +11.55^2)
= 23.09
the length of the longer leg of triangle ABC = BC
consider one of the small triangles: sin30 = 10/BC
so BC = 10/sin30 = 10/0.5 = 20
the length of the shorter leg of triangle ABC = AC
consider the other small triangles: sin60 = 10/AC
so AC = 10/sin60 = 10/0.866 = 11.55
the length of the hypotenuse of triangle ABC = AB
= sqrt (BC^2 + AC^2) = sqrt (20^2 +11.55^2)
= 23.09