Chemical reaction: NaHCO₃ + HCl → NaCl + H₂CO₃.
H₂CO₃ → H₂O + CO₂.
If amount of sodium bicarbonate (NaHCO₃) is 1 mol, then from from reaction we can calculate amount of carbon dioxide:
n(NaHCO₃) . n(CO₂) = 1 : 1.
n(CO₂) = 1 mol.
At standard pressure and temperature:
V(CO₂) = n(CO₂) · Vm
V(CO₂) = 1 mol · 22,4 L/mol.
V(CO₂) = 22,4 L.