Human body temperatures are normally distributed with a mean of 98.20°f and a standard deviation of 0.62of. find the temperature that separates the top 7% from the bottom 93%. round your answer to the nearest hundredth.

Respuesta :

Find the probability area bound by 93% or 0.93.
0.5 lies to the left of the mean value.
0.93−0.5=0.43 lies to the right of mean.
Find the corresponding z value for 0.43.
It is 1.48.

Use this value to determine the required x value.
You have to use the formula -

z=x−μσ

Solve it for x

x=z⋅σ+μ

Where;

x=?
z=1.48
σ=0.62
μ=98.20

Now put these values in the formula;

x=(1.48⋅0.62)+98.20=0.9176+98.20=99.1176 = 99.12

Temperature that separates top 7% from the bottom 93% is 99.12.