Question

1. A group of 12 people enjoy different hobbies, 2 enjoy art, 6 enjoy knitting and 4 enjoy quilting. A person is chosen at random.

What is the probability that the person enjoys knitting or quilting?
2/3
1/2
5/6
1/3

2. Adam has 10 coins in his pocket. He has 2 nickels, 3 quarters, 2 dimes and 3 pennies. Adam chooses a coin at random.

What is the probability that he selects a nickel or a dime from his pocket?
2/5
3/5
4/5
1/2

3. Jamie rolls a pair of six-sided number cubes.

What is the probability that the sum of the numbers on the number cubes is either a multiple of 5 or an odd number?
5/9
25/36
7/12
2/3

4. In a group of 30 people, 9 people study French and 14 people study Spanish. Seven people study both French and Spanish.

What is the probability of studying French or Spanish?
7/50
7/30
23/30
8/15

5. A and B are two events.

P(A)=0.5 , P(B)=0.4 and P(A and B)=0.3 .

What is the value of P(A or B) ?
0.2
0.3
0.4
0.6

Answer 1

Answer:

1. 5/6

2. 2/5

3. 2/3

4. 8/15

5. 0.6

Step-by-step explanation:

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Answer 2

1) The probability that the person enjoys knitting or quilting is; 5/6

2) The probability that he selects a nickel or a dime from his pocket is; 2/5

3) The probability that the sum of the numbers on the number cubes is either a multiple of 5 or an odd number is; 2/3

4) The probability of studying French or Spanish is; 8/15

5) The value of P(A or B) is; 0.6

1) Sample size; N = 12

Number that enjoy art = 2

Number that enjoy knitting = 6

Number that enjoy quilting = 4

P(enjoys knitting or quilting) = (6 + 4)/12

P(enjoys knitting or quilting) = 10/12 = 5/6

2) Sample size; N = 10

Number of nickels = 2 nickels

Number of quarters = 3 quarters

Number of dimes = 2 dimes

Number of pennies = 3 pennies

P(nickel or a dime) = (2 + 2)/10

P(nickel or a dime) = 2/5

3) A cube has 6 sides.

Thus, total number of possible combinations is;

6 × 6 = 36

Numbers that their Sum are either multiple of 5 or an odd number = 24

Thus;

P(the sum of the numbers on the number cubes is either a multiple of 5 or an odd number) = 24/36 = 2/3

4) Sample size; N = 30

P(study French) = 9

P(study Spanish) = 14

P(study French and Spanish) = 7

Thus,

P(study French or Spanish) = (9 + 7)/30

P(study French or Spanish) = 16/30 = 8/15

5) P(A) = 0.5

P(B) = 0.4

P(A and B) = 0.3

P(A or B) would be gotten from the formula events that are not mutually exclusive;

P(A or B) = P(A) + P(B) - P(A and B)

P(A or B) = 0.5 + 0.4 - 0.3

P(A or B) = 0.6

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