Respuesta :
y = 3x +x²
[tex] \frac{dy}{dx} = d\frac{(3x+ x^{2}) }{dx} = 3 \frac{dx}{dx} +d \frac{ (x^{2}) }{dx} [/tex]
= [tex]3 + 2x \frac{dx}{dx} = 3+2x[/tex]
[tex] \frac{dy}{dx} = d\frac{(3x+ x^{2}) }{dx} = 3 \frac{dx}{dx} +d \frac{ (x^{2}) }{dx} [/tex]
= [tex]3 + 2x \frac{dx}{dx} = 3+2x[/tex]
When you have a function that is in the form of (f(x))^n, the derivative of the function will have the formula:
n * (f(x))^(n-1) * f'(x)
The given function is:
y = (3x+x^2) ^ 5
Based on the above, the derivative with respect to x would be:
5 * (3x+x^2)^(5-1) * f'(3x+x^2)
This would give a result of:
5 * (3x+x^2)^4 * (3+2x)
Comparing the calculated derivative with the given choices, the right choice would be:
B. 5 * (3x+x^2)^4 * (3+2x)
n * (f(x))^(n-1) * f'(x)
The given function is:
y = (3x+x^2) ^ 5
Based on the above, the derivative with respect to x would be:
5 * (3x+x^2)^(5-1) * f'(3x+x^2)
This would give a result of:
5 * (3x+x^2)^4 * (3+2x)
Comparing the calculated derivative with the given choices, the right choice would be:
B. 5 * (3x+x^2)^4 * (3+2x)
Otras preguntas
