Answer: The concentration of the acid Vincent produced is 0.083 M.
Explanation:
Given: Mass = 6.5 g
Volume = 600.0 mL (1 mL = 0.001 L) = 0.6 L
Moles is the mass of substance divided by its molar mass. So, moles of bromic acid (molar mass = 128.91 g/mol) are calculated as follows.
[tex]Moles = \frac{mass}{molar mass}\\= \frac{6.5 g}{128.91 g/mol}\\= 0.05 mol[/tex]
Molarity is the number of moles of a substance present in liter of a solution.
Therefore, molarity (concentration) of the given solution is calculated as follows.
[tex]Molarity = \frac{no. of moles}{Volume (in L)}\\= \frac{0.05 mol}{0.6 L}\\= 0.083 M[/tex]
Thus, we can conclude that the concentration of the acid Vincent produced is 0.083 M.
