hahdbeh38
hahdbeh38
27-11-2017
Mathematics
contestada
could someone please help!!
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thelittlebughun
thelittlebughun
27-11-2017
The first two terms of a geometric sequence are a1=1/3 and a2=1/6. what is a8 the 8th term?
r=(1/6)/(1/3) = 1/2
a(8)= ar^7 = (1/3)(1/2)^7 = 1/3*1/128= 1/384
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